Web18 hours ago · I have the following query that concatenates values for a given id: SELECT LISTAGG(UNIQUE(t.VALUE), ' - ') WITHIN GROUP (ORDER BY t.CREATED_DATE DESC) FROM MY_TABLE t WHERE t.id=? GROUP BY t.id; How can I modify this query to exclude the first (i.e. most recent) value? if there are 2 records, only one value should be returned WebOct 8, 2012 · Current versions of the Oracle database (patched 19c or later) have much, much better support for keeping an ordered list in one column: use a JSON array. ... , json_arrayagg(coalesce(new_support_group, old_support_group) order by grp_id) old_support_groups, any_value(column1) column1, any_value(column2) column2 from …
GROUP_ID - Oracle Help Center
WebOracle GROUP BY Clause is an expression or keyword which groups a result set into subsets that have matching values for one or more columns. To get the result set in groups or need to apply aggregate or GROUP function with the Non-GROUP Functional column, Oracle GROUP BY Clause is a good option. Recommended Articles WebThe HZ_PARTIES table stores basic information about parties. Although a record in the HZ_PARTIES table represents a unique party, multiple parties can have the same name. The parties can be one of three types: Organization(for example, Oracle Corporation), Person(for example, Jane Doe), Group(for example, World Wide Web Consortium) Party reocrds can … bistro nights sheffield
Introducing to Oracle GROUPING SETS by Practical Examples
WebIdentifying Existing User and Group IDs. To create identical users and groups, you must identify the user ID and group IDs assigned them on the node where you created them, … WebThe Oracle/PLSQL GROUP_ID function assigns a number to each group resulting from a GROUP BY clause. The GROUP_ID function is most commonly used to identify duplicated … WebAug 14, 2024 · Sorted by: 2 select "ID", max ("Relevant") as "Relevant", "LongDescription", max ("A") as "A", max ("B") as "B", max ("C") as "C", listagg ("Comment", ' // ') within group (order by null) as "Comment" from dummyTable group by "ID", "LongDescription" order by "ID"; http://www.sqlfiddle.com/#!4/af6db4/15 Share Improve this answer Follow darts player with long hair